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Program : Program to display hexadecimal equivalent of a i/p binary number.
<![CDATA[ /* Prg. to display hexadecimal equivalent of a i/p binary number */
#include <stdio.h>
#include <conio.h>
#include <math.h>
int btod(int b[]);
void dtoh(int s);
int c;
void main()
{
int a[5],d,i,e,f,g,s;
clrscr();
printf("\n\n\nWhat will be the length of input no.? ");
scanf("%d",&c);
printf("Don't exceed input from your input limit or 5 digits in any case");
printf("\nEnter no.:- ");
scanf("%d",&d);
for (i=c-1;i>=0;--i)
{
e = pow(10,i);
a[i] = d/e;
d = d%e;
}
s=btod(a);
dtoh(s);
printf("\n\n\n\n\n\t\t\tHAVE A NICE DAY! BYE.");
getch();
}
int btod(int b[])
{
int k,s=0,i,n;
n=*b;
for (i=c-1;i>=0;--i)
{
if (i>0)
*b=*(b+i);
else
*b=n;
if (*b==1)
{
k=pow(2,i);
s=s+k;
}
}
return(s);
}
void dtoh(int s)
{
int b,c=0,a[5],i=0;
b=s;
while (b>15)
{
a[i]=b%16;
b=b/16;
i++;
c++;
}
a[i]=b;
printf("\nIts hexadecimal equivalent is ");
for (i=c;i>=0;--i)
{
if (a[i]==10)
printf("A");
else if (a[i]==11)
printf("B");
else if (a[i]==12)
printf("C");
else if (a[i]==13)
printf("D");
else if (a[i]==14)
printf("E");
else if (a[i]==15)
printf("F");
else
printf("%d",a[i]);
}
return;
}]]>
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